Hydroxy ipronidazole-d3
Based on 1 Customer Validation
Hydroxy ipronidazole-d3 is the deuterium labeled Hydroxy ipronidazole. Hydroxy ipronidazole (Ipronidazole-OH) is a metabolite of nitroimidazole antibiotics, such as ipronidazole (IPZ). Hydroxy ipronidazole may has similar mutagenic potential as the parent compound.
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- Purity: 99.89%
- CAS No.: 1156508-86-9
- 화학식: C7H8D3N3O3
- 분자량:188.20
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보관:Powder -20°C, 3 years ; In solvent -80°C, 6 months , -20°C, 1 month
All Endogenous Metabolite Isoforms
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Biological Activity
Stable heavy isotopes of hydrogen, carbon, and other elements have been incorporated into drug molecules, largely as tracers for quantitation during the drug development process. Deuteration has gained attention because of its potential to affect the pharmacokinetic and metabolic profiles of drugs[1].
MedChemExpress (MCE) has not independently confirmed the accuracy of these methods. They are for reference only.
1. This compound can be used as a tracer
2. This compound can be used as an internal standard for quantitative analysis by NMR, GC-MS, or LC-MS.
Chemical Information
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CAS No. 1156508-86-9
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Unlabeled Cas 35175-14-5
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Appearance Solid
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분자량 188.20
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화학식 C7H8D3N3O3
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Color white
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SMILES
CC(O)(C1=NC=C([N+]([O-])=O)N1C([2H])([2H])[2H])C
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선적
Room temperature in continental US; may vary elsewhere.
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보관
Powder -20°C 3 years In solvent -80°C 6 months -20°C 1 month
순도&문서
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Data Sheet (270 KB)
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SDS (392 KB)
- English - EN (392 KB)
- Français - FR (392 KB)
- Deutsch - DE (392 KB)
- Norwegian - NO (392 KB)
- Español - ES (392 KB)
- Swedish - SV (392 KB)
- Italian - IT (392 KB)
- Korean - KR (392 KB)
- Portuguese - PT (392 KB)
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Handling Instructions (2659 KB)
References
[1]. Russak EM, et al. Impact of Deuterium Substitution on the Pharmacokinetics of Pharmaceuticals. Ann Pharmacother. 2019;53(2):211-216. [Content Brief]
[2]. Kamila Mitrowska, et al. Transfer of nitroimidazoles from contaminated beeswax to honey. Food Addit Contam Part A Chem Anal Control Expo Risk Assess.2017 Apr;34(4):573-581. [Content Brief]
Calculators
Concentration (start) × Volume (start) = Concentration (final) × Volume (final)