Fenticonazole
Based on 4 publication(s) in Google Scholar
Fenticonazole is an imidazole derivative with antibacterial and antifungal activity. Fenticonazole has the potential for the research of mixed vaginitis.
연구목적의 판매만을 진행합니다. 환자를 대상으로 한 판매는 하지 않습니다.
- CAS No.: 72479-26-6
- 화학식: C24H20Cl2N2OS
- 분자량:455.40
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보관:
Please store the product under the recommended conditions in the Certificate of Analysis.
Publications Citing Use of MedChemExpress (MCE) Fenticonazole
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Biological Activity
Chemical Information
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CAS No. 72479-26-6
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분자량 455.40
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화학식 C24H20Cl2N2OS
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SMILES
ClC1=CC=C(C(Cl)=C1)C(OCC2=CC=C(SC=3C=CC=CC3)C=C2)CN4C=NC=C4
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선적
Room temperature in continental US; may vary elsewhere.
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보관
Please store the product under the recommended conditions in the Certificate of Analysis.
Publications (4)
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Journal Impact Factor
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Most Recent
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Pharmacol Res
Identification of the anti-fungal drug fenticonazole nitrate as a novel PPARγ-modulating ligand with good therapeutic index: Structure-based screening and biological validation. [Abstract]2021 Nov:173:105860. PMID: 34461220 -
Bioorg Chem
Structure-based screening and biological validation of the anti-thrombotic drug-dicoumarol as a novel and potent PPARγ-modulating ligand. [Abstract]2022 Dec:129:106191. PMID: 36270169 -
Molecules
Identification of Novel PPARγ Partial Agonists Based on Virtual Screening Strategy: In Silico and In Vitro Experimental Validation. [Abstract]2024 Oct 15;29(20):4881. PMID: 39459249 -
BMC Cancer
Single-cell transcriptional signature-based drug repurposing and in vitro evaluation in colorectal cancer. [Abstract]2024 Mar 25;24(1):371. PMID: 38528462
순도&문서
References
[1]. Tumietto F, et al. Looking for appropriateness in the cure of mixed vaginitis: the role of fenticonazole as an empiric treatment. Future Microbiol. 2019;14:1349-1355. [Content Brief]
[2]. Veronese M, et al. Fenticonazole, a new imidazole derivative with antibacterial and antifungal activity. In vitro study. Arzneimittelforschung. 1981;31(12):2133-2137. [Content Brief]
Calculators
Concentration (start) × Volume (start) = Concentration (final) × Volume (final)