2,4,6-Trimethylphenol-d11
2,4,6-Trimethylphenol-d11 is the deuterium labeled 2,4,6-Trimethylphenol. 2,4,6-Trimethylphenol is a probe compound shown to react mainly with organic matter (3DOM*). 2,4,6-Trimethylphenol is rapidly oxidized by singlet oxygen in aqueous solution.
For research use only. We do not sell to patients.
- CAS No.: 362049-45-4
- Formula: C9HD11O
- Molecular Weight:147.26
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Storage:
Please store the product under the recommended conditions in the Certificate of Analysis.
Biological Activity
Stable heavy isotopes of hydrogen, carbon, and other elements have been incorporated into drug molecules, largely as tracers for quantitation during the drug development process. Deuteration has gained attention because of its potential to affect the pharmacokinetic and metabolic profiles of drugs[1].
MedChemExpress (MCE) has not independently confirmed the accuracy of these methods. They are for reference only.
1. This compound can be used as a tracer
2. This compound can be used as an internal standard for quantitative analysis by NMR, GC-MS, or LC-MS.
Chemical Information
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CAS No. 362049-45-4
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Molecular Weight 147.26
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Formula C9HD11O
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SMILES
OC1=C(C([2H])=C(C([2H])=C1C([2H])([2H])[2H])C([2H])([2H])[2H])C([2H])([2H])[2H]
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Shipping
Room temperature in continental US; may vary elsewhere.
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Storage
Please store the product under the recommended conditions in the Certificate of Analysis.
Purity & Documentation
References
[1]. Russak EM, et al. Impact of Deuterium Substitution on the Pharmacokinetics of Pharmaceuticals. Ann Pharmacother. 2019 Feb;53(2):211-216. [Content Brief]
[2]. Rosado-Lausell SL, et al. Roles of singlet oxygen and triplet excited state of dissolved organic matter formed by different organic matters in bacteriophage MS2 inactivation. Water Res. 2013;47(14):4869-4879. [Content Brief]
[4]. Libby RD, et al. Defining the involvement of HOCl or Cl2 as enzyme-generated intermediates in chloroperoxidase-catalyzed reactions. J Biol Chem. 1992;267(3):1769-1775. [Content Brief]
Calculators
Concentration (start) × Volume (start) = Concentration (final) × Volume (final)