2',6'-Dihydroxy-4'-methoxydihydrochalcone
2',6'-Dihydroxy-4'-methoxydihydrochalcone is an orally active dihydrochalcone compound with antiplasmodial and anti-inflammatory activities. 2',6'-Dihydroxy-4'-methoxydihydrochalcone reduces the IL-1β, TNF, and nitrite levels in vitro.
For research use only. We do not sell to patients.
- CAS No.: 35241-55-5
- Formula: C16H16O4
- Molecular Weight:272.30
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Storage:
Please store the product under the recommended conditions in the Certificate of Analysis.
All Parasite Isoforms
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Biological Activity
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Cell Line
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Type | Value | Description | References |
|---|---|---|---|---|
| B16-F10 | IC50 |
373 μM
Compound: 5
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Cytotoxicity against mouse B16-F10 cells assessed as reduction in cell viability incubated for 72 hrs by XTT assay
Cytotoxicity against mouse B16-F10 cells assessed as reduction in cell viability incubated for 72 hrs by XTT assay
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[PMID: 27720556] |
| KB | ED50 |
>10 μg/mL
Compound: 1
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Cytotoxicity against human KB cells after 72 hrs
Cytotoxicity against human KB cells after 72 hrs
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[PMID: 8158163] |
| NCI-H187 | IC50 |
9.7 μM
Compound: 1b
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Cytotoxicity against human NCI-H187 cells after 5 days by Resazurin Microplate Assay
Cytotoxicity against human NCI-H187 cells after 5 days by Resazurin Microplate Assay
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[PMID: 20362442] |
Chemical Information
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CAS No. 35241-55-5
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Molecular Weight 272.30
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Formula C16H16O4
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SMILES
O=C(C1=C(O)C=C(OC)C=C1O)CCC2=CC=CC=C2
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Structure Classification
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Initial Source
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Shipping
Room temperature in continental US; may vary elsewhere.
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Storage
Please store the product under the recommended conditions in the Certificate of Analysis.
Purity & Documentation
References
[1]. Cerutti ML,et al. Effects of 2',6'-dihydroxy-4'-methoxydihidrochalcone on innate inflammatory response. Naunyn Schmiedebergs Arch Pharmacol. 2020 Nov;393(11):2061-2072. [Content Brief]
[2]. Bénédicte Portet, et al. Activity-guided isolation of antiplasmodial dihydrochalcones and flavanones from Piper hostmannianum var. berbicense. Phytochemistry. 2007 May;68(9):1312-20. [Content Brief]
Calculators
Concentration (start) × Volume (start) = Concentration (final) × Volume (final)