Fmoc-Ser(tBu)-OH-15N
Fmoc-Ser(tBu)-OH-15N is the 15N labeled Fmoc-Ser(tBu)-OH. Fmoc-Ser(tBu)-OH is a serine derivative.
For research use only. We do not sell to patients.
- CAS No.: 387867-79-0
- Formula: C22H2515NO5
- Molecular Weight:384.43
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Storage:
4°C, sealed storage, away from moisture
* In solvent : -80°C, 6 months; -20°C, 1 month (sealed storage, away from moisture)
Biological Activity
Stable heavy isotopes of hydrogen, carbon, and other elements have been incorporated into drug molecules, largely as tracers for quantitation during the drug development process. Deuteration has gained attention because of its potential to affect the pharmacokinetic and metabolic profiles of drugs[1].
MedChemExpress (MCE) has not independently confirmed the accuracy of these methods. They are for reference only.
1. This compound can be used as a tracer
2. This compound can be used as an internal standard for quantitative analysis by NMR, GC-MS, or LC-MS.
Chemical Information
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CAS No. 387867-79-0
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Unlabeled Cas 71989-33-8
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Appearance Solid
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Molecular Weight 384.43
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Formula C22H2515NO5
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Color White to light yellow
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SMILES
CC(C)(C)OCC(C(O)=O)[15NH]C(OCC1C2=CC=CC=C2C3=CC=CC=C31)=O
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Shipping
Room temperature in continental US; may vary elsewhere.
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Storage
4°C, sealed storage, away from moisture
* In solvent : -80°C, 6 months; -20°C, 1 month (sealed storage, away from moisture)
Purity & Documentation
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Data Sheet (269 KB)
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SDS (252 KB)
- English - EN (252 KB)
- Français - FR (252 KB)
- Deutsch - DE (252 KB)
- Norwegian - NO (252 KB)
- Español - ES (252 KB)
- Swedish - SV (252 KB)
- Italian - IT (252 KB)
- Korean - KR (252 KB)
- Portuguese - PT (252 KB)
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Handling Instructions (2659 KB)
References
[1]. Russak EM, et al. Impact of Deuterium Substitution on the Pharmacokinetics of Pharmaceuticals. Ann Pharmacother. 2019 Feb;53(2):211-216. [Content Brief]
[2]. Luckose F, et al. Effects of amino acid derivatives on physical, mental, and physiological activities. Crit Rev Food Sci Nutr. 2015;55(13):1793-1144. [Content Brief]
Calculators
Concentration (start) × Volume (start) = Concentration (final) × Volume (final)