Acipimox-d4
Based on 1 Customer Validation
Acipimox-d4 is the deuterium labeled Acipimox. Acipimox (K-9321), a nicotinic acid analogue, is an antilipolytic compound. Acipimox acutely inhibits lipolysis and suppresses systemic levels of free fatty acids (FFAs) and improves insulin sensitivity.
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- CAS No.: 1246816-28-3
- 화학식: C6H2D4N2O3
- 분자량:158.15
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보관:
Please store the product under the recommended conditions in the Certificate of Analysis.
Biological Activity
Stable heavy isotopes of hydrogen, carbon, and other elements have been incorporated into drug molecules, largely as tracers for quantitation during the drug development process. Deuteration has gained attention because of its potential to affect the pharmacokinetic and metabolic profiles of drugs[1].
MedChemExpress (MCE) has not independently confirmed the accuracy of these methods. They are for reference only.
1. This compound can be used as a tracer
2. This compound can be used as an internal standard for quantitative analysis by NMR, GC-MS, or LC-MS.
Chemical Information
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CAS No. 1246816-28-3
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Unlabeled Cas 51037-30-0
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분자량 158.15
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화학식 C6H2D4N2O3
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SMILES
[2H]C(C1=CN=C(C(O)=O)C([2H])=[N+]1[O-])([2H])[2H]
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Synonyms
K-9321-d4
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선적
Room temperature in continental US; may vary elsewhere.
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보관
Please store the product under the recommended conditions in the Certificate of Analysis.
순도&문서
References
[1]. Russak EM, et al. Impact of Deuterium Substitution on the Pharmacokinetics of Pharmaceuticals. Ann Pharmacother. 2019;53(2):211-216. [Content Brief]
[2]. Esben Thyssen Vestergaard, et al. Short‐term acipimox treatment is associated with decreased cardiac parasympathetic modulation. Br J Clin Pharmacol. 2017 Dec; 83(12): 2671-2677. [Content Brief]
[3]. Y-L Wang-Fisher, et al. Acipimox stimulates leptin production from isolated rat adipocytes. J Endocrinol. 2002 Aug;174(2):267-72. [Content Brief]
[4]. B Ahrén. Reducing plasma free fatty acids by acipimox improves glucose tolerance in high-fat fed mice. Acta Physiol Scand. 2001 Feb;171(2):161-7. [Content Brief]
Calculators
Concentration (start) × Volume (start) = Concentration (final) × Volume (final)