(±)-Lomatin
(±)-Lomatin (Xanthogalol) (Compound 10) is a coumarin-type secondary metabolite. (±)-Lomatin can be found in Coleonema album. (±)-Lomatin can be used for the research of bacterial infections, mycobacterial infections, and fungal infections.
Para uso exclusivo en investigación. No vendemos a pacientes.
- No. CAS: 1147-25-7
- Fòrmula: C14H14O4
- Peso molecular:246.26
-
Almacenamiento:
Please store the product under the recommended conditions in the Certificate of Analysis.
Actividad biológica
Descripciòn
Cellular Effect
|
Cell Line
|
Type | Value | Description | References |
|---|---|---|---|---|
| CHO | Inhibition |
142.315 %
Compound: LOMATIN
|
Inhibition of sodium fluorescein uptake in OATP1B3-transfected CHO cells at an equimolar substrate-inhibitor concentration of 10 uM
Inhibition of sodium fluorescein uptake in OATP1B3-transfected CHO cells at an equimolar substrate-inhibitor concentration of 10 uM
|
[PMID: 23571415] |
| CHO | Inhibition |
92.9117 %
Compound: LOMATIN
|
Inhibition of sodium fluorescein uptake in OATP1B1-transfected CHO cells at an equimolar substrate-inhibitor concentration of 10 uM
Inhibition of sodium fluorescein uptake in OATP1B1-transfected CHO cells at an equimolar substrate-inhibitor concentration of 10 uM
|
[PMID: 23571415] |
In Vitro
(±)-Lomatin (Xanthogalol) (Compound 10) (0.019-2.5 mg/mL; 24 h) inhibits the growth of E. coli, P. aeruginosa, E. faecalis, S. aureus, C. albicans, and M. tuberculosis with MIC values ranging from 0.156 mg/mL to 1 mg/mL[1].
MedChemExpress (MCE) has not independently confirmed the accuracy of these methods. They are for reference only. .
Chemical Information
-
No. CAS 1147-25-7
-
Peso molecular 246.26
-
Fòrmula C14H14O4
-
SMILES
O=C1OC2=C(C=C1)C=CC=3OC(C)(C)C(O)CC32
-
Synonyms
Xanthogalol
-
Structure Classification
-
Initial Source
-
Envío
Room temperature in continental US; may vary elsewhere.
-
Almacenamiento
Please store the product under the recommended conditions in the Certificate of Analysis.
Pureza y Documentación
Referencias
Calculators
Concentration (start) × Volume (start) = Concentration (final) × Volume (final)