Thiamphenicol (Standard)
Based on 1 Customer Validation
Thiamphenicol (Standard) is the analytical standard of Thiamphenicol. This product is intended for research and analytical applications. Thiamphenicol (Thiophenicol), a methyl-sulfonyl derivative of Chloramphenicol, is a broad-spectrum antimicrobial antibiotic. Thiamphenicol acts by binding to the 50S ribosomal subunit, leading to inhibition of protein synthesis and bacteriostatic effect (against Gram-negative, Gram-positive aerobic and anaerobic bacteria).
연구목적의 판매만을 진행합니다. 환자를 대상으로 한 판매는 하지 않습니다.
- Purity : 99.77%
- CAS No.: 15318-45-3
- 화학식: C12H15Cl2NO5S
- 분자량:356.22
-
보관:
Please store the product under the recommended conditions in the Certificate of Analysis.
Product Information
Information
신청
The compound is the grade of analytical standard, which is the reference standard supplied assay. It is commonly used in qualitative, quantitative and methodological research experiments in HPLC, GC and MS.
Chemical Information
-
CAS No. 15318-45-3
-
Appearance Solid
-
분자량 356.22
-
화학식 C12H15Cl2NO5S
-
Color White to off-white
-
SMILES
O=C(N[C@H](CO)[C@H](O)C1=CC=C(S(=O)(C)=O)C=C1)C(Cl)Cl
-
Synonyms
Thiophenicol (Standard); Dextrosulphenidol (Standard)
-
선적
Room temperature in continental US; may vary elsewhere.
-
보관
Please store the product under the recommended conditions in the Certificate of Analysis.
순도&문서
-
SDS (393 KB)
- English - EN (393 KB)
- Français - FR (393 KB)
- Deutsch - DE (393 KB)
- Norwegian - NO (393 KB)
- Español - ES (393 KB)
- Swedish - SV (393 KB)
- Italian - IT (393 KB)
- Korean - KR (393 KB)
- Portuguese - PT (393 KB)
-
Handling Instructions (2659 KB)
References
[1]. A Marchese, et al. In vitro activity of thiamphenicol against multiresistant Streptococcus pneumoniae, Haemophilus influenzae and Staphylococcus aureus in Italy. J Chemother. 2002 Dec;14(6):554-61. [Content Brief]
[2]. Marta Tikhomirov, et al. Pharmacokinetics of florfenicol and thiamphenicol in ducks. J Vet Pharmacol Ther. 2019 Jan;42(1):116-120. [Content Brief]
Calculators
Concentration (start) × Volume (start) = Concentration (final) × Volume (final)