Indinavir-d6
Based on 1 Customer Validation
Indinavir-d6 is the deuterium labeled Indinavir. Indinavir (MK-639; L735524) is a potent and specific HIV protease inhibitor that appears to have good oral bioavailability.
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- CAS No.: 185897-02-3
- Formule: C36H41D6N5O4
- Masse moléculaire:619.83
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Stockage:
Please store the product under the recommended conditions in the Certificate of Analysis.
Activité biologique
Stable heavy isotopes of hydrogen, carbon, and other elements have been incorporated into drug molecules, largely as tracers for quantitation during the drug development process. Deuteration has gained attention because of its potential to affect the pharmacokinetic and metabolic profiles of drugs[1].
MedChemExpress (MCE) has not independently confirmed the accuracy of these methods. They are for reference only.
1. This compound can be used as a tracer
2. This compound can be used as an internal standard for quantitative analysis by NMR, GC-MS, or LC-MS.
Chemical Information
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CAS No. 185897-02-3
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Unlabeled Cas 150378-17-9
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Masse moléculaire 619.83
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Formule C36H41D6N5O4
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SMILES
CC(C)(C)NC([C@H](CN(CC1)C([2H])([2H])C2=C([2H])N=C([2H])C([2H])=C2[2H])N1C[C@@H](O)C[C@@H](CC3=CC=CC=C3)C(N[C@H]4C5=CC=CC=C5C[C@H]4O)=O)=O
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Synonyms
MK-639-d6 free base; L-735524-d6 free base
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Livraison
Room temperature in continental US; may vary elsewhere.
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Stockage
Please store the product under the recommended conditions in the Certificate of Analysis.
Pureté et documentation
Références
[1]. Russak EM, et al. Impact of Deuterium Substitution on the Pharmacokinetics of Pharmaceuticals. Ann Pharmacother. 2019;53(2):211-216. [Content Brief]
[2]. Stein, D.S., et al., A 24-week open-label phase I/II evaluation of the HIV protease inhibitor MK-639 (indinavir). AIDS, 1996. 10(5): p. 485-92. [Content Brief]
[3]. Liu, F., et al., Kinetic, stability, and structural changes in high-resolution crystal structures of HIV-1 protease with drug-resistant mutations L24I, I50V, and G73S. J Mol Biol, 2005. 354(4): p. 789-800. [Content Brief]
Calculators
Concentration (start) × Volume (start) = Concentration (final) × Volume (final)